Question

A Car accelerates uniformly from 18 km h to 36 km h in 5 minutes calculate acceleration and distance hcover by car bin that time

Answer 1

Heya user !!!

Here's the answer you are looking for

Initial speed of the car (u) = 18km/h = 5m/s

Final speed of the car (v) = 36km/h = 10m/s

Time taken (t) = 5min = 300sec

Using the 1st equation of motion,

v = u + at where a is the acceleration

10 = 5 + 300a

300a = 5

a = 1/60 = 0.01667 m/s²

Now, using the 3rd equation of motion,

v² - u² = 2as where s is the distance covered.

10² - 5² = 2(1/60) s

100 - 25 = 1/30×s

75 = s/30

s = 75 × 30 = 2250m


Therefore the acceleration is 0.01667m/s² and the distance covered in that time is 2250m.


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