A Car accelerates uniformly from 18 km h to 36 km h in 5 minutes calculate acceleration and distance hcover by car bin that time
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Heya user !!!
Here's the answer you are looking for
Initial speed of the car (u) = 18km/h = 5m/s
Final speed of the car (v) = 36km/h = 10m/s
Time taken (t) = 5min = 300sec
Using the 1st equation of motion,
v = u + at where a is the acceleration
10 = 5 + 300a
300a = 5
a = 1/60 = 0.01667 m/s²
Now, using the 3rd equation of motion,
v² - u² = 2as where s is the distance covered.
10² - 5² = 2(1/60) s
100 - 25 = 1/30×s
75 = s/30
s = 75 × 30 = 2250m
Therefore the acceleration is 0.01667m/s² and the distance covered in that time is 2250m.
★★ HOPE THAT HELPS ☺️ ★★
Here's the answer you are looking for
Initial speed of the car (u) = 18km/h = 5m/s
Final speed of the car (v) = 36km/h = 10m/s
Time taken (t) = 5min = 300sec
Using the 1st equation of motion,
v = u + at where a is the acceleration
10 = 5 + 300a
300a = 5
a = 1/60 = 0.01667 m/s²
Now, using the 3rd equation of motion,
v² - u² = 2as where s is the distance covered.
10² - 5² = 2(1/60) s
100 - 25 = 1/30×s
75 = s/30
s = 75 × 30 = 2250m
Therefore the acceleration is 0.01667m/s² and the distance covered in that time is 2250m.
★★ HOPE THAT HELPS ☺️ ★★
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