Science, asked by roli1103deoria, 9 months ago

A car accelerates uniformly from 18 km/h
to 36 km/h in 5 seconds. Calculate the dis-
tance covered by the car during that time.

Answers

Answered by k047

Given parameters

Time taken (t) = 5 sec

Initial velocity (u) =18 km/hour

u=18×1000/60×60s

u = 5 m/s

Final velocity (v) =36km/hour

v=36×1000/60×60s

v =10 m/s

We need to calculate acceleration and distance traveled

We know that

acceleration a = (v – u)/t

Substituting the given values in the above equation we get,

a = (10 – 5)/5

a =5/5

a = 1 m/s2

We know that distance travelled is calculated by the formula

Distance travelled S = u t + (1/2) a × t2

Substituting the given values in the above equation we get,

S = 5 × 5 + (1/2) × 1 × 52

S = 25 + (1/2) × 25

S = 25 + 12.5

S = 37.5 m

Hence

acceleration a =1 m/s2

Distance travelled S =37.5 m

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Answered by Anonymous

Answer:

37.5m

Explanation:

Time taken (t) = 5 sec

Initial velocity (u) =18 km/hour

$u = \frac{18*1000}{60*60\\ s}\\\\u = 5m/s$

Final velocity (v) =36km/hour

$v = \frac{36*1000}{60*60\\s}$ v =10 m/s

We need to calculate acceleration and distance traveled

We know that

acceleration a = (v – u)/t

Substituting the given values in the above equation we get,

a = (10 – 5)/5

a =5/5

a = 1 m/s2

We know that distance travelled is calculated by the formula

Distance travelled S = u t + (1/2) a × t2

Substituting the given values in the above equation we get,

S = 5 × 5 + (1/2) × 1 × 52

S = 25 + (1/2) × 25

S = 25 + 12.5

S = 37.5 m

Hence

acceleration a =1 m/s2

Distance travelled S =37.5 m

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A car accelerates uniformly from 18 km/hto 36 km/h in 5 seconds. Calculate the dis-tance covered by the car during that time.​

Answers

A car accelerates uniformly from 18 km/h
to 36 km/h in 5 seconds. Calculate the dis-
tance covered by the car during that time.