a car accelerates uniformly from 18 km/h to 36 km/h in 5 seconds.calculate the acceleration
Answers
Answered by
4
Acceleration = Change in Velocity/Time
Change in Velocity = 36-18 = 18 km/h=5 m/s
Time= 5 Seconds
Acceleration = 5/5= 1 m/s2
Equation of motion,s=ut+(1/2)at2
u=18 km/h=5 m/s
t=5 s
a=1 m/s2
s= (5*5)+(1/2*1*5*5)
s=25+12.5 i.e., s=37.5 m
Change in Velocity = 36-18 = 18 km/h=5 m/s
Time= 5 Seconds
Acceleration = 5/5= 1 m/s2
Equation of motion,s=ut+(1/2)at2
u=18 km/h=5 m/s
t=5 s
a=1 m/s2
s= (5*5)+(1/2*1*5*5)
s=25+12.5 i.e., s=37.5 m
lalita2074:
its 5/18
Answered by
3
18 kmph= 18×5/18 ms
=5ms
36kmph×5/18= 10ms
a =v-u/t
a=10-5/ 5
a=5/5
a=1m/s2
=5ms
36kmph×5/18= 10ms
a =v-u/t
a=10-5/ 5
a=5/5
a=1m/s2
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