Question

A car accelerates uniformly from 18 km h to 36 km h in 5 s.

Calculate (1) the acceleration and (11) the distance covered by the car in that time.​

Answer 1

initial veloctiy, u = 18km/h

u = 18 × ( 5/18 ) m/s

u = 5 m/s

final velocity, v = 36 km/h

v = 36 × ( 5/18 ) m/s

v = 10 m/s

Time taken, t = 5 seconds

( 1 )

Acceleration, a = ( v – u ) / t

a = ( 10 – 5 ) / 5

a = 5 / 5

a = 1m/s²

( 2 )

Distance covered :

s = ut + 1/2 at²

s = 5(5) + 1/2 (1)(5)²

s = 25 + 1/2 × 25

s = 25 + 12.5

s = 37.5 m

Answer 2

Answer:

I)1 m/s²,s=37.5 m

Explanation:

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