Question

A car accelerates uniformly from 18 km/h to 36 km/h in 5 sec. Calculate 1 The acceleration and 2 The distance travelled by the car in that time.

Answer 1

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initial velocity = 18km/h >> 5 m/s

Final velocity = 36km/h >> 10m/s

time = 5 sec

To Find-: acceleration and distance

⏩Acceleration

we know
v=u+at

$10=5+a5$

$10-5=a5$

$5=a5$

$\huge{a=1m/s^2}$

⏩distance
we know

v^2-u^2=2as

$10^2-5^2=2*1*s$
$100-25=2s$
$75=2s$
$\huge{s=75/2 >> 57.5m}$

Answer 2

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Given :-

U = 18 km/h = $18×\frac{1000}{3600}$=5 m/s

V = 36 km/h = $36×\frac{1000}{3600}$=10 m/s

T = 5 s

A = ?

S = ?

Let's find the 1 Acceleration :

A = $\frac{V - U}{T}$

A = $\frac{10-5}{5}$

A = 1 m/${s}^{2}$

Let's find the 2 Distance :

S = UT + $\frac{1}{2}\:A{T}^{2}$

S = 5 × 5 $\frac{1}{2}\:1\:×{5}^{2}$

S = 25 + 12.5

S = 37.5 m

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