Question

a car accelerates uniformly from 18 km/h to 36 km/h in 5s the distance covered by the carin that time is​

Answer 1

Answer:

⇒ a = 1 m/s². Hence, the acceleration of the car is 1 m/s². ⇒ s = 37.5 m. Hence, the distance covered by car is 37.5

Answer 2

Answer:

Given parameters

Time taken (t) = 5 sec

Initial velocity (u) =18 km/hour

 

\(u = \frac{18\times 1000}{60\times 60s}\)

 

u = 5 m/s

Final velocity (v) =36km/hour

 

\(v = \frac{36\times 1000}{60\times 60s}\)

 

v =10 m/s

We need to calculate acceleration and distance traveled

We know that

acceleration a = (v – u)/t

Substituting the given values in the above equation we get,

a = (10 – 5)/5

a =5/5

a = 1 m/s2

We know that distance travelled is calculated by the formula

Distance travelled S = u t + (1/2) a × t2

Substituting the given values in the above equation we get,

S = 5 × 5 + (1/2) × 1 × 52

S = 25 + (1/2) × 25

S = 25 + 12.5

S = 37.5 m

Hence

acceleration a =1 m/s2

Distance travelled  S =37.5 m