Question

A car accelerates uniformly from 18 km/h to 36 km /h m 5s.

calculate:-
a) The acceleration and
b)The distance covered by the Car in that time.

please answer !!!​

Answer 1

$\large\underline{\bigstar \: \: {\sf Given-}}$

• Car accelerates uniformly with speed ${\sf u=18\:km/h\:and \: v=36\:km/h}$
• Time (t) = 5s

$\large\underline{\bigstar \: \: {\sf To \: Find-}}$

• Acceleration
• Distance covered by car

$\large\underline{\bigstar \: \: {\sf Formula \: Used -}}$

$\implies\underline{\boxed{\sf a=\dfrac{v-u}{t}}}$

$\implies\underline{\boxed{\sf s=ut+\dfrac{1}{2}at^2}}$

$\large\underline{\bigstar \: \: {\sf Solution -}}$

$\bullet\underline{\rm Convert \: km/h \: to \: m/s}$

$\implies{\sf u=18\:km/h }$

$\implies{\sf 18\times \dfrac{5}{18}}$

$\implies{\bf u=5\:m/s}$

$\implies{\sf v=36\:km/h}$

$\implies{\sf 36\times \dfrac{5}{18}}$

$\implies{\bf v=10\:m/s }$

Now ,

a) Acceleration -

$\implies{\sf a=\dfrac{v-u}{t}}$

$\implies{\sf a=\dfrac{10-5}{5}}$

$\implies{\sf a=\dfrac{5}{5}}$

$\implies{\bf Acceleration \: (a)=1\: m/s^2 }$

b) Distance covered by car -

$\implies{\sf s=ut+\dfrac{1}{2}at^2 }$

$\implies{\sf s=5\times 5+\dfrac{1}{2}\times 1 \times (5)^2}$

$\implies{\sf s=25+\dfrac{1}{2}\times 25}$

$\implies{\sf s = 25+12.5}$

$\implies{\bf s = 37.5\:m }$

$\large\underline{\bigstar \: \: {\sf Answer-}}$

Acceleration of the car is 1 m/s²

Distance covered by car is 37.5 m

Answer 2

Answer:

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