Question

A car accelerates uniformly from 18 km h to 36km h in 2 sec calculate acceleration and distance cover by car in that time

Answer 1

18×5/18=5m/s

36×5/18=10m/s

a=v-u/t

a=10-5/2

a=5/2

a=2.5m/s^2

s=ut+1/2at^2

s=5×2+1/2×2.5×2^2

s=10+1/2×2.5×4

s=10+1/2×10

s=10+5

s=15km

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