Question

A car accelerates uniformly from 18 km h to 36km h in 5 sec calculate acceleration and distance cover by car in that time in km per hour

Answer 1

$v - u \div t$
18-36÷5
3.6

Answer 2

u=18km/hr

v=36km/hr

t=5sec=5/3600

a=v-u/t=36-18/5/3600=2*3600/5=1440km/hr*hr

s=v^2-u^2/2a=1296-324/2880=972/2880=0.3375km