Physics, asked by quinnolivia45, 10 days ago

A car accelerates uniformly from 18 km/h to 72 km/h in 15, s. calculate the accelaration

Answers

Answered by pratyush1493
0

Answer:

Given :-

Time taken = 10 sec

Initial velocity = 18 km/h

To Find :-

The acceleration of the car.

Solution :-

We know that,

u = Initial velocity

t = Time

v = Final velocity

a = Acceleration

Using the formula,

Given that,

Time taken (t) = 10 sec

Initial velocity (u) = 18 km/h = 5 m/s

Final velocity (v) = 72 km/h = 20 m/s

Substituting their values,

20 = 5 + (a) × 10

a = (v - u)/t

a = (20 - 5)/10

a = 15/10

a = 1.5 m/s²

Therefore, the acceleration of the car is 1.5 m/s².

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Answered by Anonymous
7

Provided that:

  • Initial velocity = 18 kmph
  • Final velocity = 72 kmph
  • Time = 15 seconds

To calculate:

  • The acceleration

Solution:

  • The acceleration = 1 mps sq.

Using concepts:

  • Formula to convert kmph-mps

• To calculate the acceleration we can use either first equation of motion or acceleration formula.

Using formulas:

Acceleration formula:

  • a = (v-u)/t

First equation of motion:

  • v = u + at

Formula to convert kmph-mps:

  • 1 kmph = 5/18 mps

Where, a denotes acceleration, u denotes initial velocity, v denotes final velocity and t denotes time taken.

Required solution:

~ Firstly let us convert kmph-mps!

Converting initial velocity that is in kmph into mps...

→ 1 kmph = 5/18 mps

→ 18 kmph = 18 × 5/18 mps

→ 18 kmph = 1 × 5/1 mps

→ 18 kmph = 5 mps

  • Henceforth, converted!

Converting final velocity into mps...

→ 1 kmph = 5/18 mps

→ 72 kmph = 72 × 5/18 mps

→ 72 kmph = 4 × 5/1 mps

→ 72 kmph = 20 mps

  • Henceforth, converted!

~ Now by using suitable formula let us find out the acceleration!

By using acceleration formula...

→ a = (v-u)/t

→ a = (20-5)/15

→ a = 15/15

→ a = 1 mps sq.

Acceleration = 1 mps sq.

By using first equation of motion...

→ v = u + at

→ 20 = 5 + a(15)

→ 20 - 5 = 15a

→ 15 = 15a

→ a = 15/15

→ a = 1 mps sq.

→ Acceleration = 1 mps sq.

Additional information:

\begin{gathered}\boxed{\begin{array}{c}\\ {\pmb{\sf{Three \: equation \: of \: motion}}} \\ \\ \sf \star \: v \: = u \: + at \\ \\ \sf \star \: s \: = ut + \: \dfrac{1}{2} \: at^2 \\ \\ \sf \star \: v^2 - u^2 \: = 2as\end{array}}\end{gathered}

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