A car accelerates uniformly from 18 km/h to 72 km/h in 15, s. calculate the accelaration
Answers
Answer:
Given :-
Time taken = 10 sec
Initial velocity = 18 km/h
To Find :-
The acceleration of the car.
Solution :-
We know that,
u = Initial velocity
t = Time
v = Final velocity
a = Acceleration
Using the formula,
Given that,
Time taken (t) = 10 sec
Initial velocity (u) = 18 km/h = 5 m/s
Final velocity (v) = 72 km/h = 20 m/s
Substituting their values,
20 = 5 + (a) × 10
a = (v - u)/t
a = (20 - 5)/10
a = 15/10
a = 1.5 m/s²
Therefore, the acceleration of the car is 1.5 m/s².
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Provided that:
- Initial velocity = 18 kmph
- Final velocity = 72 kmph
- Time = 15 seconds
To calculate:
- The acceleration
Solution:
- The acceleration = 1 mps sq.
Using concepts:
- Formula to convert kmph-mps
• To calculate the acceleration we can use either first equation of motion or acceleration formula.
Using formulas:
• Acceleration formula:
- a = (v-u)/t
• First equation of motion:
- v = u + at
• Formula to convert kmph-mps:
- 1 kmph = 5/18 mps
Where, a denotes acceleration, u denotes initial velocity, v denotes final velocity and t denotes time taken.
Required solution:
~ Firstly let us convert kmph-mps!
Converting initial velocity that is in kmph into mps...
→ 1 kmph = 5/18 mps
→ 18 kmph = 18 × 5/18 mps
→ 18 kmph = 1 × 5/1 mps
→ 18 kmph = 5 mps
- Henceforth, converted!
Converting final velocity into mps...
→ 1 kmph = 5/18 mps
→ 72 kmph = 72 × 5/18 mps
→ 72 kmph = 4 × 5/1 mps
→ 72 kmph = 20 mps
- Henceforth, converted!
~ Now by using suitable formula let us find out the acceleration!
By using acceleration formula...
→ a = (v-u)/t
→ a = (20-5)/15
→ a = 15/15
→ a = 1 mps sq.
→ Acceleration = 1 mps sq.
By using first equation of motion...
→ v = u + at
→ 20 = 5 + a(15)
→ 20 - 5 = 15a
→ 15 = 15a
→ a = 15/15
→ a = 1 mps sq.
→ Acceleration = 1 mps sq.
Additional information: