Question

a car accelerates uniformly from 18 km/ hour to 72 km per hour in 10 s. calculate the acceleration of the car ​

Answer 1

Answer:

1.5 m/s²

Step-by-step explanation:

Step 1- Change km/hr into m/s

18km/hr to m/s = (18x1000)÷ 3600 = 5m/s

72km/hr to m/s = (72x1000)÷ 3600 = 20m/s

Step 2- Use acceleration formula

acceleration= (v-u)÷t

= (20-5)÷ 10

= 1.5 m/s²

HOPE U FIND THIS SUM EASIER NOW!!

Answer 2

Given :-

Time taken = 10 sec

Initial velocity = 18 km/h

To Find :-

The acceleration of the car.

Solution :-

We know that,

• u = Initial velocity
• t = Time
• v = Final velocity
• a = Acceleration

Using the formula,

$\underline{\boxed{\sf First \ equation \ of \ motion=v=u+at}}$

Given that,

Time taken (t) = 10 sec

Initial velocity (u) = 18 km/h = 5 m/s

Final velocity (v) = 72 km/h = 20 m/s

Substituting their values,

20 = 5 + (a) × 10

a = (v - u)/t

a = (20 - 5)/10

a = 15/10

a = 1.5 m/s²

Therefore, the acceleration of the car is 1.5 m/s².