Question

a car accelerates uniformly from 18 km/ hr from 36 km / hr in 5 seconds calculate the acceleration and the distance covered by the car in that time​

Answer 1

Answer:

24

Explanation:

18 or 36 ka hcf lo to 24 ata ha

Answer 2

Answer:

a = 1 m/s^2 , D = 37.5m

Explanation:

First of all convert the speed from Km/hr to m/s because the time is given in seconds.

18 km/hr = 18 × 5/18 = 5 m/s

36 km/hr = 36 × 5/18 = 10 m/s

$acceleration \: = \frac{change \: in \: velocity}{change \: in \: time } \\ acceleration \: = \frac{10 - 5}{5}$

acceleration = 5/5 = 1 m/s^2 or 1 ms^-2

Now, Final velocity (v) = 10m/s

Initial velocity (u) = 5m/s

a = 1 m/s^2

Displacement (s) = ?

$v {}^{2} - u {}^{2} = 2as \\ {10}^{2} - {5}^{2} = 2 \times 1 \times s$

=> 100 - 25 = 2s

=> s = 75/2 = 37.5 m