a car accelerates uniformly from 18 km per hour to 36 km per hour in 5 seconds calculate the acceleration the distance covered by the car in her that time
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hey dear
here is your answer
given data :
initial velocity (u) = 18 km/hr or 5 m/s
final velocity (v) = 36 km/hr or 10 m/s
time taken (t) = 5 seconds
to find : acceleration & distance
here we go
solution : for acceleration
by using first equation of motion
v = u+at
10 = 5+5a
a =5/5
a = 1 m/s²
solution : for distance
by using third equation of motion
v² = u²+2as
(10)² = (5)²+2*1*s
100 = 25+2s
2s = 75
s = 37.5 meter
hope it helps :)
here is your answer
given data :
initial velocity (u) = 18 km/hr or 5 m/s
final velocity (v) = 36 km/hr or 10 m/s
time taken (t) = 5 seconds
to find : acceleration & distance
here we go
solution : for acceleration
by using first equation of motion
v = u+at
10 = 5+5a
a =5/5
a = 1 m/s²
solution : for distance
by using third equation of motion
v² = u²+2as
(10)² = (5)²+2*1*s
100 = 25+2s
2s = 75
s = 37.5 meter
hope it helps :)
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