A car accelerates uniformly from 18 kmph to 72 kmph in 5 s. The acceleration of the car (in m/sq.s) is:
A) 3 B) 5 C) 6 D) 7
Answers
Answered by
4
Answer:
plz refer the above attachment
Attachments:
Answered by
20
A car accelerates uniformly from 18 kmph to 72 kmph in 5 s.
We have to find the acceleration of the car.
From above data we have; initial velocity of the car is 18 km/hr, final velocity is 72 km/hr and time is 5 sec.
Firstly convert km/hr into m/s. To do this, multiply the given value by 5/18.
⇒ u = 18×5/18 = 5 m/s and v = 72×5/18 = 20 m/s
Using the First Equation Of Motion:
v = u + at
Substitute the known values in the above formula,
→ 20 = 5 + a(5)
→ 20 - 5 = 5a
→ 15 = 5a
Divide by 5 on both sides,
→ 15/5 = 5a/5
→ 3 = a
Therefore, the acceleration of the car is 3 m/s².
Option A) 3 [ Answer ]
Similar questions