A car accelerates uniformly from 18km/h in 5sec. Calculate the accelaration and the distance covered by the car in that time.
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Answer:
Explanation:
time=5sec
u=0
v=18km/h=5m/s
a=v-u by t
=5-0 by 5
=5 by 5
=1 m/s
Equation of motion,s=ut+(1/2)at2
u=18 km/h=5 m/s
t=5 s
a=1 m/s2
s= (5*5)+(1/2*1*5*5)
s=25+12.5 i.e., s=37.5 m
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