A car accelerates uniformly from 18km h to 36 km h 5 s calculate.
a) The acceleration.
b) The distance covered by the car in the time.
c) Find out the equation for position - time relation.
d) Explain the second law of motion.
Answers
Answered by
1
Answer:
a 3.5
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Answered by
1
Explanation:
Initial speed = u = 18 km/hr = 5 m/s
Final sped = v = 36 km/hr = 10 m/s
==>acceleration a = (v-u)/t = (10-5)/5 = 1 m/s^2
==>Distance travelled S = u t + (1/2) a t^2 = 5×5 + (1/2)×1×5^2 = 37.5 m
==>s=ut+1/2at^2 (a=(v-u)t)
s=ut+1/2((v-u)/t)t²
s=ut+((v-u)/2)*t
s=t(u+(v-u)/2)
s=t(2u+v-u)/2
s=t(v+u)/2
==>Newton's second law of motion can be formally stated as follows: The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.
HOPE YOU UNDERSTOOD WELL AND THIS MIGHT HAD HELPED YOU..........
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