Physics, asked by pathakshresth3831, 8 months ago

A car accelerates uniformly from 18km/h to 36km/h in 5 minutes then acceleration is

Answers

Answered by ıtʑFᴇᴇʟɓᴇãᴛ
4

\mathcal{\huge{\fbox{\red{Question\:?}}}}

A car accelerates uniformly from 18km/h to 36km/h in 5 minutes then what is the acceleration .

\mathcal{\huge{\fbox{\green{AnSwEr:-}}}}

➡ The acceleration of the car is 1 m/s².

\mathcal{\huge{\fbox{\purple{Solution:-}}}}

Given :-

  • A car accelerates uniformly from 18km/h to 36km/h in 5 minutes.

To Find :-

  • The acceleration of the car

Calculation :-

According to the question,

  • Initial velocity = u = 18 km/h,

Converting it into m/s,

For that we have to multiply it with 5/18,

➡ So, 18 × 5/18 = 5 m/s.

  • The final velocity = v = 36 km/s.

Converting it into m/s,

➡ So, 36 × 5/18 = 10 m/s.

Now, time taken is also given as 5 seconds,

According to the first equation of motion,

v = u + at

So, putting all the values, we get

⇒ v = u + at

⇒ 10 = 5 + a × 5

⇒ 10 - 5 = 5a

⇒ 5 = 5a

⇒ 5/5 = a

⇒ a = 1 m/s².

Hence, the acceleration of the car is 1 m/s².

___________________________________

Answered by ITzBrainlyGuy
5

Answer :-

Given,

Initial velocity=18 km/hr = 5 m/s

Final velocity=v=36km/h=10 m/s

Time taken = 5 seconds

We need to calculate acceleration and distance traveled

We know that

acceleration a = (v-u)/t

Substituting the given values in the above equation we get,

a=(10-5)/5 =5/5= 1 m/s2

We know that distance travelled is calculated by the formula

Distance travelled S = u t + (1/2) a t2

Substituting the given values in the above equation we get,

S =5×5 + (1/2)×1×52

25 + (1/2) X 25

25 + 12.5

= 37.5 m

Hence, acceleration a =1 m/s2

Similar questions