A car accelerates uniformly from 18km/h to 36km/h in 5 minutes then acceleration is
Answers
✴ A car accelerates uniformly from 18km/h to 36km/h in 5 minutes then what is the acceleration .
➡ The acceleration of the car is 1 m/s².
Given :-
- A car accelerates uniformly from 18km/h to 36km/h in 5 minutes.
To Find :-
- The acceleration of the car
Calculation :-
According to the question,
- Initial velocity = u = 18 km/h,
Converting it into m/s,
For that we have to multiply it with 5/18,
➡ So, 18 × 5/18 = 5 m/s.
- The final velocity = v = 36 km/s.
Converting it into m/s,
➡ So, 36 × 5/18 = 10 m/s.
Now, time taken is also given as 5 seconds,
According to the first equation of motion,
v = u + at
So, putting all the values, we get
⇒ v = u + at
⇒ 10 = 5 + a × 5
⇒ 10 - 5 = 5a
⇒ 5 = 5a
⇒ 5/5 = a
⇒ a = 1 m/s².
Hence, the acceleration of the car is 1 m/s².
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Answer :-
Given,
Initial velocity=18 km/hr = 5 m/s
Final velocity=v=36km/h=10 m/s
Time taken = 5 seconds
We need to calculate acceleration and distance traveled
We know that
acceleration a = (v-u)/t
Substituting the given values in the above equation we get,
a=(10-5)/5 =5/5= 1 m/s2
We know that distance travelled is calculated by the formula
Distance travelled S = u t + (1/2) a t2
Substituting the given values in the above equation we get,
S =5×5 + (1/2)×1×52
25 + (1/2) X 25
25 + 12.5
= 37.5 m
Hence, acceleration a =1 m/s2