Question

A car accelerates uniformly from 18km/h to 36km/h in 5 sec i)calculate the acceleration and ii)the distance covered by car in that time​

Answer 1

Answer:

Mark me as brainliest

Explanation:

Given,

u=18km/h=

60×60

18×1000

=5m/s

v=36km/h=

60×60

36×1000

=10m/s

t=5sec

acceleration, a=?

1st equation of motion,

v=u+at

10=5+5a

5a=5

a=

5

5

=1m/s

Answer 2

Step by step solution:-

Initial velocity of the car, u = 18 km/hr

Final velocity of the car, v = 36 km/hr

Time, t = 5 sec

According to the first equation of motion.,

$\sf\blue{\boxed{v = u + at}}$

$\sf 10 = 5 +( a \times 5)$

$\sf 10 - 5 = 5a$

$\sf 5 = 5a$

$\sf a = \dfrac{5}{5}$

$\sf a = 1 \: {m}{ {s}^{-2} }$

Acceleration of car = 1 m/s².

According to third equation of motion

$\sf \green{v}^{2} - {u}^{2} = 2as$

$\sf{(10)}^{2} - {(5)}^{2} = 2 \times 1 \times s$

$\sf 100 - 25 = 2s$

$\sf 75 = 2s$

$\sf s = \dfrac{75}{2}$

$\sf s = 37.5 \: m$

Distance travelled by the car = 37.5 m.