A car accelerates uniformly from 18Km/h to 36Km/hr in 3 seconds. Calculate the acceleration and the distance covered by the car at that time
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Answer:
u=18km/h
18×5/18
=5m/s
v=36km/h
36×5/18
=10m/s
t=3second
acceleration=10-5/3=5/3
distance=36-18=18km
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