Physics, asked by Anonymous, 1 year ago

A car accelerates uniformly from 18Km/h to 36Km/hr in 3 seconds. Calculate the acceleration and the distance covered by the car at that time

Answers

Answered by siyabhardwaj
4

Answer:

u=18km/h

18×5/18

=5m/s

v=36km/h

36×5/18

=10m/s

t=3second

acceleration=10-5/3=5/3

distance=36-18=18km

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