A car accelerates uniformly from 18km/hr to 36 km/hr in 5 sec.calculate the distance covered by the car in 5 sec.
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Initial velocity u = 18 km/h = 5 m/s
Final velocity v = 36 km/h = 10 m/s
Time t = 5 s
Let distance travelled be s and acceleration be a.
Now, v = u + at
So, 10 = 5 + a(5)
So, a = 1 m/s²
Now, s = ut + ½ at²
So, s = (5)(5) + ½ (1)(5)²
So, s = 25 + 12.5
So, s = 37.5 m
Thus, the distance covered is 37.5 metres
Final velocity v = 36 km/h = 10 m/s
Time t = 5 s
Let distance travelled be s and acceleration be a.
Now, v = u + at
So, 10 = 5 + a(5)
So, a = 1 m/s²
Now, s = ut + ½ at²
So, s = (5)(5) + ½ (1)(5)²
So, s = 25 + 12.5
So, s = 37.5 m
Thus, the distance covered is 37.5 metres
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