Question

A car accelerates uniformly from 18km/hr to 36km/hor in 5sec calculate acceleration,the distance covered by the car in that time.​

Answer 1

Acceleration = Change in Velocity/Time  

Change in Velocity = 36-18 = 18 km/h=5 m/s  

Time= 5 Seconds  

Acceleration = 5/5= 1 m/s2

Equation of motion,s=ut+(1/2)at2  

u=18 km/h=5 m/s  

t=5 s  

a=1 m/s2  

s= (5*5)+(1/2*1*5*5)

s=25+12.5 i.e., s=37.5 m  

Hope you are clear with my explanations