A car accelerates uniformly from 18km /hr to 36km/hr in 5 sec calculate the acceleration and the distance covered by the car in that time
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Answered by
8
acceleration is 5m/s
Answered by
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Intial velocity (u) = 18 km/h
= 18*5/18 ms-1
= 5 ms-1.
Final velocity (v) = 36 km/h
= 36*5/18
= 10 ms-1.
time= 5 seconds
Acceleration= v - u / t
Acceleration = 10-5/5
= 5/5 = 1 ms-2
Now
Distance = ut+1/2at^2
= 5*5 + 1/2*1*(5)^2
= 25 + 1/2*25
= 25+12.5
= 37.5 m
= 18*5/18 ms-1
= 5 ms-1.
Final velocity (v) = 36 km/h
= 36*5/18
= 10 ms-1.
time= 5 seconds
Acceleration= v - u / t
Acceleration = 10-5/5
= 5/5 = 1 ms-2
Now
Distance = ut+1/2at^2
= 5*5 + 1/2*1*(5)^2
= 25 + 1/2*25
= 25+12.5
= 37.5 m
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