Question

A car accelerates uniformly from 18km hr to 36km hr in 5sec. Find acceleration and distance covered by car in that time.

Answer 1

Given

Initial Velocity = 18 km/h = 18*5/18= 5m/s
Final velocity =36km/h = 36*5/18= 10m/s

a=v-u/t
a=10-5/5
a=1m/s²

Now distance

s=ut +1/2at²
s= 5*5 +1/2 *1*5*5
s=25 + 12.5
s=37.5

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