Question

A car accelerates uniformly from 18km per hour to 36km per hour in 5 seconds . Calculate the acceleration and the distance covered by the car in that time.

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Answer 1

$\large\bold{\underline{GIVEN :}}$

•Initial velocity=18 km/hr = 5 m/s

•Final velocity=v=36km/h=10 m/s

•Time taken = 5 seconds

$\large\bold{\underline{SOLUTION :}}$

We need to calculate acceleration and distance travelled,

We know that

$\red{\boxed{\tt{ a \:=\: (v-u)/t}}}$

Substituting the given values in the above equation we get,

a=(10-5)/5 =5/5= 1 m/s²

$\bold{\boxed{\red{\tt{ a = 1 m/s^2}}}}$

We know that distance travelled is calculated by the formula

Distance travelled$\bold{\boxed{\red{\tt{ S = u t + (1/2) at^2}}}}$

Substituting the given values in the above equation we get,

S =5×5 + (1/2)×1×52

25 + (1/2) × 25

25 + 12.5

$\bold{\boxed{\red{\tt{S = 37.5 m}}}}$

Hence,

Acceleration (a) =1 m/s².

Distance travelled (S) =37.5 m.

Answer 2

HOPE THIS HELPS U...

@HARSHA