A car accelerates uniformly from 18km to 36km per hour in 5 sec. Calculate (1) The acceleration and (2) distance corvered by car in that time
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Answer:
acceleration-1 m/sec square
distance covered- 37.5 m
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Answered by
0
ANSWER:
acceleration:–1m/s2
distance:–37.5m
EXPLANATION:
u=18km/hr=(18*5/18)m/s=5m/s
v=36km/hr=(36*5/18)m/s=10m/s
so,acceleration=(v–u/t)=(10–5/5)m/s2=1m/s2
t=5s
so,by S=ut+1/2at2
S=5m/s*5s+1/2*1m/s2*5s*5s
=25m+1/2*1m/s2*25s2
=25m+12.5m
=37.5m
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