Question

a car accelerates uniformly from 18kmh to 36kmh in 5sec calculate the acceleration

Answer 1

Answer:

A = v-u/t

A =36-18/5

= 18/5

Acceleration = 3.6kmh

Answer 2

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$given -$

$initial \: velocity = 18kmph$

$final \: velocity = 36kmph$

$time \: taken = 5sec$

$18 \times \frac{5}{18}$

$5m \: per \: sec$

$36 \times \frac{5}{18}$

$10 \: m \: per \: sec$

$a = \frac{v - u}{t}$

$a = \frac{10 - 5}{5}$

$a = \frac{5}{5}$

$a = 1 \: m \: {s}^{2}$