Question

A car accelerates uniformly from 20 km/h to 35 km/h in 5 seconds.Calculate the acceleration. ​

Answer 1

Answer:

$\bigstar{\bold{Acceleration\:=\:0.832\:m/s^{2} }}$

Explanation:

$\Large{\underline{\underline{\bf{Given:}}}}$

• Initial velocity (u) = 20 km/hr = 5.56 m/s
• Final velocity (v) = 35 km/hr = 9.72 m/s
• Time taken (t) = 5 s

$\Large{\underline{\underline{\bf{To\:Find:}}}}$

• Acceleration of the car (a)

$\Large{\underline{\underline{\bf{Solution:}}}}$

→ Acceleration is given by the formula

 a = (v - u)/t

→ Substituting the given datas we get,

  a = (9.72 - 5.56)/5

  a = 4.16/5

  a = 0.832 m/s²

$\boxed{\bold{Acceleration\:=\:0.832\:m/s^{2} }}$

$\Large{\underline{\underline{\bf{Notes:}}}}$

→ Acceleration is defined as the change of velocity with respect to time

   a = (v - u)/t

→ Acceleration is a vector quantity. It's unit is m/s²

Answer 2

Answer:

Given-

Initial velocity (u)=20km/h=20*1000/3600=50/9 m/s

Final velocity (v)=35km/h=35*1000/3600=175/18 m/s

Time taken(t)=5 seconds

To Find-

Acceleration of the car(a)

Solution-

To find the value of a ,we have to use the first equation of motion

=v=u+at

=175/18=50/9+a*5

=a=50/9 * 18/175+5

=a=2*2/7+5

=a=4/7+5

=a=39/7 m/s

Hope it helps you

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