Question

A car accelerates uniformly from 20 km/h to 35 km/h in 5 s. Calculate (a) the acceleration and (b) the distance covered by the car in this time. *
Your answer

please answer fast 50 points

Answer 1

Answer:

A car accelerates uniformly from 20 km/h to 35 km/h in 5 s. Calculate (a) the acceleration and (b) the distance covered by the car in this time. *

Your answer

please answer fast 50 points

Answer 2

Here is ur answer ,

what is acceleration ?

• change in the velocity of an object per unit time.
• Acceleration a = v- u / t
• S.I unit = m/s^2
• Here , u = initial velocity and v= final velocity

a = acceleration , t = time

i) u = 20 km/h = 5.5m/s

v = 35 km/h = 9.7 .. m/s

t = 5 seconds

a = v- u / t

a = 9.7 - 5.5 / 5

a = 4.2 / 5

a = 0.84 m/s ^2

ii) The Distance covered

s = ut + 1/2 at^2

Here, s = distance travelled by the object

t = time

a = uniform acceleration

s = 5.5 × 5+ 1/2 ( 0.84) (5)^2

s = 27.5 + 1/2 × 0.84 × 25

s = 27.5 + 10.5

s = 38m

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