Question

A car accelerates uniformly from 22.5 m/s to 46.1 m/s in 2.47 seconds. Determine the acceleration of the car.

Answer 1

Answer:

Here, initial velocity is u=18.5m/s and final velocity is v=46.1m/s

Time taken t=2.47s

If a be the acceleration of the car.

Using v=u+at,

46.1=18.5+a(2.47)

⟹ a=11.17m/s

2

If S be the distance traveled by car.

Using formula v

2

−u

2

=2aS,

(46.1)

2

−(18.5)

2

=2(11.17)S

⟹ S=79.8m

Step-by-step explanation:

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