Question

.A car accelerates uniformly from 30 m/s to 48 m/s in 3 seconds.Calculate the acceleration of the car and

distance covered by the car in first 3 seconds.​

Answer 1

Answer:

acceleration is equals to 6 m/s^2

distance covered is equals to 117 m

Explanation:

given:

u=30m/s. v=48m/s

t=3s

v=u+at

48=30+a×3

a=6m/s^2

S=ut+1/2×at^2

S=90+27

S=117m

Answer 2

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