A car accelerates uniformly from 36 km h–1 to 54 km h–1 in 10 s. Calculate (i) the acceleration and (ii) the distance covered by the car in that time.
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final velocity= 54 km/h
= 15m/s
initial velocity = 36km/h
= 10m/s
time taken= 10second
acceleration= v- u/t
= 15-10/10
= 5/10
= 1/2
= 0.5
distance covered= v²- u² = 2as
= 15² - 10² = 2×0.5× s
= 225- 100= 10× s
= 125 = 10s
s = 12.5
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