Question

A car accelerates uniformly from 36 km/h to 108 km/h in 10 s. The acceleration produced by car is A)20 m/s² B)3 m/s² C)2 m/s² D)30 m/s²​

Answer 1

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Given parameters

Time taken (t) = 5 sec

Initial velocity (u) =18 km/hour

u

=

18

×

1000

60

×

60

s

u = 5 m/s

Final velocity (v) =36km/hour

v

=

36

×

1000

60

×

60

s

v =10 m/s

We need to calculate acceleration and distance travelled

We know that

acceleration a = (v – u)/t

Substituting the given values in the above equation we get,

a = (10 – 5)/5

a =5/5

a = 1 m/s2

We know that distance travelled is calculated by the formula

Distance travelled S = u t + (1/2) a × t2

Substituting the given values in the above equation we get,

S = 5 × 5 + (1/2) × 1 × 52

S = 25 + (1/2) × 25

S = 25 + 12.5

S = 37.5 m

Hence

acceleration a =1 m/s2

Distance travelled S =37.5 m

Answer 2

answer:
C) 2 m/s^2
Step-by-Step explanation:
final velocity(v)=108 km/h
=108*5/18 m/s
=30 m/s
initial velocity(u)=36 km/h
=36*5/18 m/s
=10 m/s
Time(t)= 10 s
Acceleration=v-u/t
=30-10/10
=20/10
=2 m/s^2