Question

A car accelerates uniformly from 36 km/h to 45 km/h in 15 s. Calculate the distance

covered by the car in that time.​

Answer 1

Given parameters

Time taken (t) = 5 sec

Initial velocity (u) =18 km/hour

\(u = \frac{18\times 1000}{60\times 60s}\)

u = 5 m/s

Final velocity (v) =36km/hour

\(v = \frac{36\times 1000}{60\times 60s}\)We know that distance travelled is calculated by the formula

Distance travelled S = u t + (1/2) a × t2

Substituting the given values in the above equation we get,

S = 5 × 5 + (1/2) × 1 × 52

S = 25 + (1/2) × 25

S = 25 + 12.5

S = 37.5 m

Hence

acceleration a =1 m/s2

Distance travelled S =37.5 m

Pls mark as brainlest...