Question

A car accelerates uniformly from 36 km/hr to 54km/hr in
10s. Calculate
(1) Acceleration
(1) Distance covered by the car​

Answer 1

Answer:

u = 36 ×1000/3600 = 10 m/s

v = 54×1000/3600 = 15 m/s

v = u + at

15 = 10 + a ×10

15-10 = a ×10

5 = a × 10

a = 2 m/ s ^2

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Answer 2

Answer :-

U = 36 km/hr = 10m/s

V = 54km/hr = 15 m/s

Acceleration =

V = u + at

15 = 10+ a * 10

15-10 = a* 10

5 = a *t

a = 5/10

a = 0.5 m/s^2

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