A car accelerates uniformly from 36km/h to 72km/h in10s.Calculate the
distance covered by the car
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Answer:
s= 150 meter
Explanation:
given
u= 36km/h = 36×5/18= 10m/s
v= 72km/h= 72×5/18= 20m/s
t= 10 sec
since v= u +at
20= 10+a×10
10a= 10
a= 1 m/sec²
since
v²= u²+2as
20² = 10²+2×1×s
2s= 400-100= 300
s= 300/2
s= 150 meter
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