Question

A car accelerates uniformly from 54 km/hr to 108 km/hr in 10 seconds. find acceleration of car , distance travelled by the car ​

Answer 1

u=54km/hr= 54×5/18=15m/s

v=108kmph= 30m/s

t=10s

a=v-u/t= 30-15/10= 1.5m/s^2

v^2=u^2+2as

900= 225+ 2×1.5×s

675=3s=225m

so, the distance traveled by the car is 225 m.

Answer 2

Here is your answer.. .

let us convert speed in m/s

so 54 km/h = 54 × 5/18 = 15 m/s

similarly, 108km/h = 108 × 5/18 = 30 m/s.

as we know that acceleration is the rate of change of velocity...

so here a = (30-15)/10

a = 15/10

a = 1.5 m/s^2

now we know that

by 3rd equation of motion

v^2 - u^2 = 2as

here v=30m/s

u = 15 m/s

and a= 1.5 m/s^2

so...

(30)^2 - (15)^2 = 2 × 1.5 × s

900 - 225 = 3 × s

675 = 3×s

s = 675/3

s = 225 m

i.e diatance travelled is 225m and acceleration is 1.5 m/s^2....

Hope this will help u

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