Question

a car accelerates uniformly from 54 km per hour to 72 km per hour in 10 seconds calculate acceleration metre per second square distance covered by the bus in metres during the interval

Answer 1

it is based on the equation of motion
u=54km/hr
=
$54 \times 5 \div 18$
15m/s
v=72km/hr
=72*5/18=20m/s
using first equation
a=v-u/t
20-15/10
0.5m/s2