Question

A car accelerates uniformly from 54km/hr to 72km/hr

in 5s. calculate

a. the acceleration

b. The distance covered by the car in that time​

Answer 1

Answer:

Acceleration = Change in velocity / Time

= v - u/t

72 km/h = 72 x 5/ 18 m/s = 20m/s =

54km/h = 54 5 / 18m/s = 15m/s

Acceleration = 20-15 / 10

= 5/10

= 0.5 m/s2

To find distance we use the formula

v = u? + 2aS here v is the final

velocitiy (72km/h)

velocity(54km/h)

acceleration

distance

u is the initial

a is the

S is the

202 = 152 + 2 x 0.5 x S =

400 = 225 + 1xS

400 - 225 = S

S = 175 m

Therefore distance = 175m

Explanation:

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Answer 2

Answer:

s=175km is your answers.............