Question

A car accelerates uniformly from 5m/s to 10m/s in 5 seconds.Find it's acceleration.​

Answer 1

Answer:

MARK ME AS BRAINLIEST

Explanation:

Initial velocity of the car (u)= 5 m/s

Final velocity of the car (v) = 10 m/s

Time taken for change in velocity (t)= 5 d

Therefore acceleration (a)= [10 m/s - 5 m/s]/ 5 s = 5 m/s /5s = 1 m/s²

Distance covered during these 5 seconds, is found using the relation

s = u t + ½ a t² = 5 m/s× 5 s + ½ 1 m/s² × 5² s²=25 m+ 12.5 m = 37.5 m

So car covers 37.5 m during the period its velocity changes from 5 m/s to 10 m/s.

Answer 2

बहुत सरल उत्तर 1 m/s.

Explanation:

प्रारंभिक गति = 5

अंतिम गति = 10

समय = 5

त्वरण = (10 - 5)/5

=5/5

=1m/s