Question

A car accelerates uniformly from 5m/sec to 10/sec in 5sec. the distance covered by the car in that time

Answer 1

Answer:37.5m is the answer.

Explanation:

v=u+at===>10=5+a×5==>a=1m/s²

s=ut+1/2at²===>s=5×5+1/2×1×25=37.5m

                                                  OR

Acceleration = Change in Velocity/Time

Change in Velocity =5 m/s

Time= 5 Seconds

Acceleration = 5/5= 1 m/s2

Equation of motion,s=ut+(1/2)at2

u=5 m/s

t=5 s

a=1 m/s2

s= (5*5)+(1/2*1*5*5)

s=25+12.5 i.e., s=37.5 m

Hope you are clear with my explanations

                                                            OR

Solution,

Here, We have initial and final velocity and time taken

Now, time taken is also given as 5 seconds,  

Here, we have to find,

Acceleration and Distance covered.

According to the first equation of motion,

We know that,

v = u + at

So, putting all the values, we get

⇒ v = u + at

⇒ 10 = 5 + a × 5

⇒ 10 - 5 = 5a

⇒5 = 5a

⇒ 5/5 = a

⇒ a = 1 m/s².

Hence, the acceleration of the car is 1 m/s².

Now, we have to find the distance covered, s

According to the 3rd equation of motion,

we know that,

v² - u² = 2as

So, putting all the values again, we get

⇒ v² - u² = 2as

⇒ (10)² - (5)² = 2 × 1 × s

⇒ 100 - 25 = 2s

⇒ 75 = 2s

⇒ 75/2 = s

⇒ s = 37.5 m.

Hence, the distance covered by car is 37.5 m.

HOPE YOU UNDERSTOOD..................

THANK YOU.