Question

A car accelerates uniformly from a intial velocity of 2m/s to a final velocity of 10m/s in 8second.It then slows down uniformly to a final velocity of 4m/s in 6second.calculate the acceleration of the car during the first 8second and during the last 6 second​

Answer 1

Answer :

Given -

• Initial velocity = 2 m/s
• Final velocity = 10 m/s
• Time = 8 seconds
• Then, it slows down to velocity of 4 m/s in 6 seconds

To Find -

• Acceleration in first 8 seconds
• And acceleration during last 6 seconds

Solution -

First case :

• u = 2 m/s
• v = 10 m/s
• Time = 8 seconds

So, Acceleration = (v - u)/t

➸ a = (10 - 2)/8

➸ a = 8/8

➸ a = 1 m/s²

Second case :

• u = 10 m/d
• v = 4 m/s
• t = 6 seconds

So, Acceleration = (v - u)/t

➸ a = (4 - 10)/6

➸ a = (-6)/6

➸ a = -1 m/s²

Hence, Acceleration in first 8 seconds is 1 m/s² and Acceleration in last 6 seconds is -1 m/s².