Question

A car accelerates uniformly from an initial velocity 2 metre per second to final velocity v metre per second in each second if then loss down uniformly to a final velocity for metre per second in 6 seconds calculate the acceleration of the car during the first second and first second and last second

Answer 1

Using the formula (a=v-u/t).

Initial velocity will stay the same. : U=2m/s

Final velocity will change. : v1=10m/s

Time will change too. : t=8sec

We will get that according to part : (10-2/8)=1m/s²

V2=4m/s

T2=6sec

And solution of part 2 is : (4-2/6) = 0.33m/s²

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Answer 2

Answer:

• Average speed= distance covered/elapsed time
• 20 = 100/elpased time
• elpased time= 100/20=5 sec
• Also,
• Average velocity= initial velocity(u) + final velocity (v) /2
• substituting given value
• 20= 4+25/2 final velocity (v) 25m per sec
• 4 = 40-25 = 15 m per sec
• acceleration (a) = v-u/t = 25-15/5 = 10/5=2 m per sec