Question

A car accelerates uniformly from an initial velocity 32 m/s to a final velocity of 10 m/s in 8 seconds.It then slows down uniformly to a final velocity of 4 m/s in 6 seconds. Calculate the acceleration of the car during last 6 seconds.

Answer 1

There will be a deceleration of 1m/s2 in the last 6 seconds.
u= 10m/s
v=4m/s
t=6 s
Using the equation of motion v=u+at
4= 10+6a
-6=6a
a= -1m/s2