Question

a car accelerates uniformly from an initial velocity of 2 metre per second to A final velocity of 10 M per second in 8 second it then slows down uniformly to A final velocity of 4 metre per second in 6 seconds calculate the acceleration of the car during the first 8 second hand during the last 6 seconds

Answer 1

Acceleration of the car in first 8 seconds= (V-u) /t =(10-2)/8=1m/s²


Acceleration of the car in last 6 seconds= (V-u) /t =(4-10)/6= -1m/s²