Question

a car accelerates uniformly from an initial velocity of 2 metre per second to A final velocity of 10 M per second in 8 second it then slows down uniformly to A final velocity of 4 metre per second in 6 seconds calculate the acceleration of the car during the first 8 second hand during the last 6 seconds

Answer 1

Using the formula (a=v-u/t).
Initial velocity will stay the same. : U=2m/s

Final velocity will change. : v1=10m/s

Time will change too. : t=8sec

We will get that according to part : (10-2/8)=1m/s²


V2=4m/s

T2=6sec

And solution of part 2 is : (4-2/6) = 0.33m/s²