A car accelerates uniformly from an initial velocity of 2 m/s to final velocity 10m/ਸ in 8 s. It then slows down uniformly to a final velocity 4m/s in 6s calculate the accelaertion in first 8s and last 6
Answers
ANSWER:
➡Acceleration in 1st 8 seconds
= 1 m/s²
= 1 m/s²➡ Retardation produced by brakes in last 6 seconds
= 1 m/s²➡ Retardation produced by brakes in last 6 seconds = -1 m/s²
Explanation:
given that,
A car accelerates uniformly from an initial velocity of 2 m/s to final velocity 10m/s in 8 s
here,
initial velocity of the the car = 2m/s
final velocity of car = 10 m/s
time taken for accelerating = 8 seconds
by the equation of motion
v = u + at
initial velocity(u) = 2 m/s
final velocity (v) = 10 m/s
time = 8 seconds
putting the values,
10 = 2 + a(8)
10 = 2 + 8a
8a = 10 - 2
8a = 8
a = 8/8
a = 1 m/s²
acceleration in 1st 8 seconds =
1 m/s²
now,
also given that,
It then slows down uniformly to a final velocity 4m/s in 6s
so,
here,
initial velocity of car (u) = 10 m/s
final velocity of car (v) = 4 m/s
time for deceleration (t) = 6 s
now,
by the motion equation,
v = u + at
putting the values
4 = 10 + a(6)
6a + 10 = 4
6a = 4 - 10
6a = -6
a = -6/6
a = -1 m/s²
negative acceleration shows the Retardation .
so,
Retardation produced by brakes in last 6 seconds = -1 m/s²
ANSWER:
➡Acceleration in 1st 8 seconds
= 1 m/s²
➡ Retardation produced by brakes in last 6 seconds