Question

a car accelerates uniformly from rest and travels a distance of 375 m while accelerating form 5 m/s-1 to 10 m/s-1. how long did it take to achieve a speed of 20 m/s-1, and what will be the speed after a further 2 km.

Answer 1

Answer:

it should be on the speed of 45 km/hr

Answer 2

Answer:

Explanation:

v = 10√13 m/s = 36.06 m/s  

2 log v = log 2 + log a + log s  

2 (∆v/v) = 0 + (∆ a/a) + (∆ s/s)  

2 (∆v/v) = (0.5/6.5) + (1/100) = 1/13 + 1/100 = 0.07 + 0.01 = 0.08 = 8%  

∆ v = 10√13 × (0.08) =( 4√13)/5 = 2.88 m/s  

v ± ∆ v = (36. 1 ± 2.9) m/s.