Question

A car accelerates uniformly from rest to 18 km/h in 5 seconds. What is the acceleration of the car in m/s? pls do it i recommend stary soul to do thi

Answer 1

Given :

• Initial Velocity (u) = 0 m/s

• Final Velocity (v) = 18 km/hr

• Time (t) = 5 seconds

To Find :

• Acceleration of the car (a)

Solution :

Let us convert the final velocity into it's standard form i.e.

$\rightarrow \sf \: 18 \times \dfrac{5}{18}$

$\rightarrow \sf \: \cancel \dfrac{90}{18}$

$\rightarrow \sf \:5m {s}^{ - 1}$

Let's find the acceleration now. We know that, acceleration is measure of the change in velocity of an object per unit time.

★ Acceleration = Final Velocity - Initial Velocity/Time taken

→ a = $\sf \dfrac{5 - 0}{5}$

→ a = $\sf \cancel\dfrac{5}{5}$

→ a = 1 m/s²

$\therefore$ Acceleration produced by the car is 1 m/s².

Answer 2

Answer:

Given :

• Initial Velocity (u) = 0 m/s

• Final Velocity (v) = 18 km/hr

• Time (t) = 5 seconds

To Find :

• Acceleration of the car (a)

Solution :

Let us convert the final velocity into it's standard form i.e.

\rightarrow \sf \: 18 \times \dfrac{5}{18}→18×

18

5

\rightarrow \sf \: \cancel \dfrac{90}{18}→

18

90

\rightarrow \sf \:5m {s}^{ - 1}→5ms

−1

Let's find the acceleration now. We know that, acceleration is measure of the change in velocity of an object per unit time.

★ Acceleration = Final Velocity - Initial Velocity/Time taken

→ a = \sf \dfrac{5 - 0}{5}

5

5−0

→ a = \sf \cancel\dfrac{5}{5}

5

5

→ a = 1 m/s²

\therefore∴ Acceleration produced by the car is 1 m/s².