Question

A car accelerates uniformly from rest to a speed of 7.10m/s over a distance of 35.4m . Determine the acceleration of the car.​

Answer 1

From the third equation of motion,
v^2-u^2=2as
7.1^2-0^2=2(35.4)a
50.41-0=70.8(a)
a=50.41/70.8
a=712m/s^2

Hope it helps you!

Answer 2

Answer:

$v^{2}=u^{2} +2as$

$v=7.1ms^{-1} ,$ $u=0,$ $s=35.4m$

$a=\frac{v^{2} }{2s}$ $=\frac{7.1^{2} }{2*35.4} = 0.712ms^{-2}$

Hope it helps, please mark me as brainliest, thanks! :)