A car accelerates uniformly from the 18 km per hour to the 36 km per hour in 5 second calculate the acceleration and second first the distance covered by the car in that time
Answers
Answered by
0
initial velocity u=18km/h=5m/s
final velocity v=36km/h=36x1000/60x60=10m/s
time t=5sec.
let acceleration =a
using the formula,
v=u+at
10=5+ax5
5a=5
a=1m/s²
ii)let distance travel be 'S'
using the formula,
S=ut+1/2at²
S=5x5+1/2x1x(5)²
S=25+25/2
S=50+25/2
S=75/2
S=37.5m
Hence, the required distance travel is 37.5 metres.
final velocity v=36km/h=36x1000/60x60=10m/s
time t=5sec.
let acceleration =a
using the formula,
v=u+at
10=5+ax5
5a=5
a=1m/s²
ii)let distance travel be 'S'
using the formula,
S=ut+1/2at²
S=5x5+1/2x1x(5)²
S=25+25/2
S=50+25/2
S=75/2
S=37.5m
Hence, the required distance travel is 37.5 metres.
Similar questions